Re: [docbook-apps] customizing output of <see> in index

[Michael Smith <smith@xml-doc.org>]

I can't see any reason why you should be getting that error. Your
customization layer looks correct.

What XSLT engine are you using? Have you tried opening up the
generated *.fo file in a text editor? What does the content of it
look like?

Cheryl Chase <cheryl@isna.org> writes:

> I would like to have my index say:
> 
>     photgraphy; see medical photography
> 
> rather than the docbook default:
> 
>     photography (see medical photography)
> 
> I located the "see" code in fo/autoidx.xsl and copied it to my  
> customization layer as shown below. Without making any changes to  
> "see" code, validation generates the error shown below the code. Does  
> this code need to be customized in some other context?
> 
> 
> <?xml version="1.0" encoding="UTF-8"?>
> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
>                 xmlns:fo="http://www.w3.org/1999/XSL/Format";
>                 version="1.0">
> 
> <xsl:import href="docbook-xsl-1.69.1/fo/docbook.xsl"/>
> 
> 
> 
> <xsl:template match="indexterm" mode="index-see">
>    <xsl:param name="scope" select="."/>
>   <xsl:param name="role" select="''"/>
>   <xsl:param name="type" select="''"/>
> 
>    <fo:inline>
>      <xsl:text> (</xsl:text>
>      <xsl:call-template name="gentext">
>        <xsl:with-param name="key" select="'see'"/>
>      </xsl:call-template>
>      <xsl:text> </xsl:text>
>      <xsl:value-of select="see"/>
>      <xsl:text>)</xsl:text>
>    </fo:inline>
> </xsl:template>
> 
> </xsl:stylesheet>
> 
>     [error] Element 'fo:wrapper' cannot be a child of 'fo:root'.

-- 
Michael Smith
http://sideshowbarker.net/

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