RE: [docbook-apps] How to generate <li><a href="xx">..</a></li>?

["Rowland, Larry" <larry.rowland@hp.com>]

You might consider using a simplelist instead:

<simplelist type="vert">
   <member><ulink url="xxx"/></member>  <!-- uses the URL for anchor text -->
   <member><ulink url="yyy">my anchor text</ulink></member>
<simplelist>

It does not generate a ul, but does not require the para elements.  If you want a symbol preceding the elements in the list, you have to provide it, something like:

   <member>&bull;&nbsp;<ulink ....

Itemized lists expect some sort of block structure element in the list items.  You could use a simpara with a role attribute and intercept it in processing, but that takes some XSLT development and really does not support what the tag means (a paragraph).

Regards,
Larry Rowland


-----Original Message-----
From: Tao Wang [mailto:dancefire@gmail.com] 
Sent: Thursday, May 13, 2010 12:49 AM
To: docbook-apps@lists.oasis-open.org
Subject: [docbook-apps] How to generate <li><a href="xx">..</a></li>?

Hi,

I'm using docbook 4.5 xhtml stylesheet xsl to generate html files. I
want to have a list of links, which should be:

-------------------
<li><a href="xxx">...</a></li>
<li><a href="xxx">...</a></li>
<li><a href="xxx">...</a></li>
-------------------

So, I use
============
<listitem><para><ulink url="xxx">...</ulink></para></listitem>
<listitem><para><ulink url="xxx">...</ulink></para></listitem>
<listitem><para><ulink url="xxx">...</ulink></para></listitem>
============

However, it generates following result
============
<li><p><a href="xxx">...</a></p></li>
<li><p><a href="xxx">...</a></p></li>
<li><p><a href="xxx">...</a></p></li>
============

I do not want <p> there. How can I generate the list of links without <p>?

-- 
Regards

Tao Wang

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