Website+XSLT=source filename?

[Thomas Jones <admin@buddhalinux.org>]

How does one go about finding out the XML source filename in XSL?

I tried to utilise the document-uri function of XSL 2.0; but am getting an 
error (probably from the xsltproc processor) about only being version 1.0 
capable.

I currently have successfully been using the following:

<snip>
<xsl:variable name="page" select="."/>
<xsl:variable name="xml_source">
    <xsl:choose>
      <xsl:when test="$page/config[@param='source']">
        <xsl:value-of select="($page/config[@param='source'])[1]/@value"/>
      </xsl:when>
      <xsl:otherwise>
        <xsl:text>index.xml</xsl:text>
      </xsl:otherwise>
    </xsl:choose>
  </xsl:variable>
</snip>
As you can see, I am having to generate a specific element to hold the source 
filename. But, given the volume of pages that I am constructing(4,000+); I 
would rather utilise a construct during transformation so that I don't need 
to alter the XML sources and add this element.

Thanks,
Thomas

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