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Subject: Re: [docbook-apps] breadcrumbs root node

You could change your select statement to require a parent on each element:


            <xsl:for-each select="$this.node/ancestor::*[parent::*]">

Since the root node does not have a parent, it would not be selected.  I have not tested it, but I think it would work.
Bob Stayton
Sagehill Enterprises
----- Original Message -----
Sent: Monday, August 03, 2009 1:21 AM
Subject: [docbook-apps] breadcrumbs root node



Has anyone figured out a way to remove the root node from breadcrumbs in their html output?


I am using the following code to generate my breadcrumbs:


<xsl:template name="breadcrumbs">

      <xsl:param name="this.node" select="."/>

      <table class="headertable">


            <td width="95%">

            <div class="breadcrumbs">

            <xsl:for-each select="$this.node/ancestor::*">

              <span class="breadcrumb-link">


                <xsl:attribute name="href">

                   <xsl:call-template name="href.target">

                   <xsl:with-param name="object" select="."/>

                   <xsl:with-param name="context" select="$this.node"/>



                <xsl:apply-templates select="." mode="title.markup"/>



             <xsl:text> &gt; </xsl:text>



<!-- And display the current node, but not as a link -->

<span class="breadcrumb-node">

   <xsl:apply-templates select="$this.node" mode="title.markup"/>



<!--add a logo to the top right corner-->

<xsl:call-template name="logo"/>





Any help would be greatly appreciated,


Kind Regards,


Laurie Burley


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