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Subject: Re: DOCBOOK: XML, XSL, texmath inlineequation not.
On Friday 30 August 2002 15:54, Jirka Kosek wrote: > On Fri, 30 Aug 2002, Doug du Boulay wrote: > > and then invoked > > <inlineequation> <alt role="tex"> \( \hat{R} = \hat{R}(X,Y,Z) \) > > </alt> <graphic fileref="figures/xc0.xbm"/> > > </inlineequation> > > > > running this via saxon and latex I do get a very nicely formatted > > equation in the resultant single page html document, but unfortunately > > the inline equation is not inline, but is wrapped front and back with > > </p><p> > > Could you show us little bit more of your document. What is before and > after your inlineequation? If you use it as inline element inside > paragraph text, stylesheets shouldn't generate <p> around <img>. > > Jirka Given the following experimental document: <section><title>4D Hyperspherical Coordinates</title> <para> We begin by defining four orthogonal axes <inlineequation> <alt role="tex"> \(W\), \(X\), \(Y\) and \(Z\) </alt> <graphic fileref="figures/xc_0.xbm"/> </inlineequation> with the unit basis vectors <inlineequation> <alt role="tex"> \(\hat{e}_w\), \(\hat{e}_x\), \(\hat{e}_y\) and \(\hat{e}_z\) </alt> <graphic fileref="figures/xc_1.xbm"/> </inlineequation>. By virtue of their orthogonality these basis vectors are completely independent such that anything that changes along W has no bearing on what happens along X, Y and Z. </para> <para> By virtue of the orthogonality of W, X, Y and Z we can exploit the generalized Pythagoras relation: <informalequation> <alt role="tex"> \begin{equation} |\hat{R}|^2 = W^2 + X^2 + Y^2 + Z^2 \end{equation} </alt> <graphic fileref="figures/xc0.xbm"/> </informalequation> to obtain the length of the vector <inlineequation> <alt role="tex"> \( \hat{R} = \hat{R}(W,X,Y,Z) \) </alt> <graphic fileref="figures/xc0a.xbm"/> </inlineequation>. </para> I then get the following html: <div class="section"><div class="titlepage"><div><h2 class="title" style="clear: both"><a name="d0e480"></a>4D Hyperspherical Coordinates</h2></div></div><p> We begin by defining four orthogonal axes </p><p><img src="figures/xc_0.xbm"></p><p> with the unit basis vectors </p><p><img src="figures/xc_1.xbm"></p><p>. By virtue of their orthogonality these basis vectors are completely independent such that anything that changes along W has no bearing on what happens along X, Y and Z. </p><p> By virtue of the orthogonality of W, X, Y and Z we can exploit the generalized Pythagoras relation: </p><div class="informalequation"><p><img src="figures/xc0.xbm"></p></div><p> to obtain the length of the vector </p><p><img src="figures/xc0a.xbm"></p><p>. </p> Hope thats sufficient? Thanks again Doug
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