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Subject: RE: [docbook] Can't open xml document in IE 6.0

Thanks for your inputs, I have tried the same it will working good, if i am 
giving my local path as DTD location. When i refer "mathml2.dtd" in  
"http://www.w3.org/TR/MathML2/dtd/mathml2.dtd"; it shows the following error 
in IE:

"A name was started with an invalid character. Error processing resource 
'file:///C:/sundar/test/bak/sample.xml'. Line 1, P...


I have attached the sample file which i was used.

A. Sunder Raajan

>From: "Mauritz Jeanson" <mj@johanneberg.com>
>To: "'Sundaraj Arumugam'" <sundaraj_a@hotmail.com>,   
>Subject: RE: [docbook] Can't open xml document in IE 6.0
>Date: Wed, 21 Jun 2006 18:00:21 +0200
> > -----Original Message-----
> > From: Sundaraj Arumugam
> > But I can't open my xml document in Internet Explorer 6.0, it
> > shows the
> > following error:
> >
> > "Reference to undeclared namespace prefix: 'mml'. Error
> > processing resource
> > 'file:///C:/sundar/test/sample.xml'. Line 15, P...
>The document will open i IE if you add a namespace declaration for MathML:
>  <mml:math xmlns:mml="http://www.w3.org/1998/Math/MathML";>
>	...
>  </mml:math>
>The information in this article from 2001 seems to still apply:
>To unsubscribe, e-mail: docbook-unsubscribe@lists.oasis-open.org
>For additional commands, e-mail: docbook-help@lists.oasis-open.org

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<?xml version="1.0"?>
<!DOCTYPE chapter PUBLIC "-//OASIS//DTD DocBook V4.5CR2//EN" "http://www.oasis-open.org/docbook/xml/4.5CR2/docbookx.dtd"; [
<!ENTITY % MATHML.prefix "mml">
<!ENTITY % equation.content "(alt?, (graphic+|mediaobject+|mml:math))">
<!ENTITY % inlineequation.content "(alt?, (graphic+|inlinemediaobject+|mml:math))">
<!ENTITY % mathml PUBLIC "-//W3C//DTD MathML 2.0//EN" "http://www.w3.org/TR/MathML2/dtd/mathml2.dtd";>
] >
<chapter id="ch001">
<title>Force-System Resultants and Equilibrium</title>
<abstract><para>Statics<beginpage pagenum="1-1"/> is a branch of mechanics that deals with the equilibrium of bodies, that is, those that are either at rest or move with constant velocity. In order to apply the laws of statics, it is first necessary to understand how to simplify force systems and compute the moment of a force. In this chapter these topics will be discussed, and some examples will be presented to show how the laws of statics are applied.</para></abstract>
<section id="ch001lev1sec1"><title>1.1. Force-System Resultants</title>
<section id="ch001lev2sec1"><title>Concurrent Force Systems</title><para>Force is a vector quantity that is characterized by its magnitude, direction, and point of application. When two forces <emphasis role="bold">F</emphasis><subscript>1</subscript> and <emphasis role="bold">F</emphasis><subscript>2</subscript> are <emphasis role="bold">concurrent</emphasis> they can be added together to form a resultant <emphasis role="bold">F</emphasis><subscript><emphasis>R</emphasis></subscript>=<emphasis role="bold">F</emphasis><subscript>1</subscript><emphasis role="bold">+F</emphasis><subscript>2</subscript> using the <emphasis role="bold">parallelogram law,</emphasis> <link linkend="ch001fig01">Figure 1.1</link>. Here <emphasis role="bold">F</emphasis><subscript>1</subscript> and <emphasis role="bold">F</emphasis><subscript>2</subscript> are referred to as components of <emphasis role="bold">F</emphasis><subscript><emphasis>R</emphasis></subscript>. Successive applications of the parallelogram law can also be applied when several concurrent forces are to be added; however, it is generally simpler to first determine the two components of each force along the axes of a coordinate system and then add the respective components. For example, the <emphasis>x, y, z</emphasis> (or Cartesian) components of <emphasis role="bold">F</emphasis> are shown in <link linkend="ch001fig02">Figure 1.2</link>. Here, <emphasis role="bold">i</emphasis>, <emphasis role="bold">j</emphasis>, <emphasis role="bold">k</emphasis> are unit vectors used to define the direction of the positive <emphasis>x, y, z</emphasis> axes, and <emphasis>F</emphasis><subscript>x</subscript>, <emphasis>F</emphasis><subscript>y</subscript>, <emphasis>F</emphasis><subscript>z</subscript> are the magnitudes of each component. By vector addition, <emphasis role="bold">F</emphasis>=<emphasis>F</emphasis><subscript>x</subscript>&thinsp;<emphasis role="bold">i</emphasis>+<emphasis>F</emphasis><subscript>y</subscript>&thinsp;<emphasis role="bold">j</emphasis>+<emphasis>F</emphasis><subscript>z</subscript>&thinsp;<emphasis role="bold">k</emphasis>. When each force in a concurrent system of forces is expressed by its Cartesian components, the resultant force is therefore
<equation id="ch001eq01" label="1.1"><mml:math xmlns:mml="http://www.w3.org/1998/Math/MathML";><mml:semantics><mml:mrow><mml:msub><mml:mi mathvariant="bold">F</mml:mi><mml:mi>R</mml:mi></mml:msub><mml:mo>=</mml:mo> <mml:mrow><mml:msub><mml:mi>F</mml:mi><mml:mi>x</mml:mi></mml:msub><mml:mi mathvariant="bold">i</mml:mi></mml:mrow><mml:mo>+</mml:mo> <mml:mrow><mml:msub><mml:mi>F</mml:mi><mml:mi>y</mml:mi></mml:msub><mml:mi mathvariant="bold">j</mml:mi><mml:mo>+</mml:mo> <mml:mrow><mml:msub><mml:mi>F</mml:mi><mml:mi>z</mml:mi></mml:msub><mml:mi mathvariant="bold">k</mml:mi></mml:mrow></mml:mrow></mml:mrow></mml:semantics></mml:math></equation>where &Sigma;<emphasis>F</emphasis><subscript>x</subscript>, &Sigma;<emphasis>F</emphasis><subscript>y</subscript>, &Sigma;<emphasis>F</emphasis><subscript>z</subscript> represent the scalar additions of the <emphasis>x, y, z</emphasis> components, respectively.<figure id="ch001fig01"><title>Addition of forces by parallelogram law.</title><mediaobject><imageobject><imagedata fileref="gr1"/></imageobject></mediaobject></figure><figure id="ch001fig02"><title>Resolution of a vector into its <emphasis>x, y, z</emphasis> components.</title><mediaobject><imageobject><imagedata fileref="gr2"/></imageobject></mediaobject></figure></para></section>

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