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Subject: [office-formula] DATEDIF (Section 6.9.2)
Three of the test cases for DATEDIF() show the expected result as a missing or null. What are the expected results of these expressions? =DATEDIF(DATE(1990;2;15); DATE(1993;9;15); "y") =DATEDIF(DATE(1990;2;15); DATE(1993;9;15); "d") =DATEDIF(DATE(1990;2;15); DATE(1993;9;15); "yd") Thanks, Eric Patterson
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