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Subject: [office-formula] DATEDIF (Section 6.9.2)


Three of the test cases for DATEDIF() show the expected result as a missing or null.  What are the expected results of these expressions?

        =DATEDIF(DATE(1990;2;15); DATE(1993;9;15); "y")
        =DATEDIF(DATE(1990;2;15); DATE(1993;9;15); "d")
        =DATEDIF(DATE(1990;2;15); DATE(1993;9;15); "yd")

Thanks,
Eric Patterson



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