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Subject: Re: [sca-j] Constructor selected for implementation instance creation



Folks,

I have a very simple view of this.

In order for a constructor parameter to be unambiguously identified as a property or as a reference, it *MUST* be
annotated with @Property or with @Reference.  Without this, there can be no name associated with the parameter
- and a property or a reference must have a name.

Yours,  Mike.

Strategist - Emerging Technologies, SCA & SDO.
Co Chair OASIS SCA Assembly TC.
IBM Hursley Park, Mail Point 146, Winchester, SO21 2JN, Great Britain.
Phone & FAX: +44-1962-818014    Mobile: +44-7802-467431  
Email:  mike_edwards@uk.ibm.com



From: C Vamsi <vamsic007@in.ibm.com>
To: sca-j@lists.oasis-open.org
Date: 27/02/2009 19:02
Subject: [sca-j] Constructor selected for implementation instance creation





Java C&I Spec (sca-javaci-1.1-spec-wd03.doc)

Section 5: Implementation Instance Creation
Lines 254-257:
  The constructor to use is selected by the container as follows:

     1. A declared constructor annotated with a @Constructor annotation.

     2. A declared constructor that unambiguously identifies all property
        and reference values.

     3. A no-argument constructor.



What does the second point above mean?

Is it that

All parameters that could be properties, no two are of the same type and
  for each parameter type there is one and only one SCA property of that
  type with @required=true

and

All parameters that could be references, no two are of the same interface
  and for each parameter type there is one and only one SCA reference of
  that interface with @required=true ?



++Vamsi
Apache Tuscany Committer  
http://tuscany.apache.org
Apache Geronimo Committer and Member of PMC  
http://geronimo.apache.org


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