Re: [xdi] XDI graph as XRIs

["Markus Sabadello" <markus.sabadello@xdi.org>]

These are two different topics:

1) Addressing - This is quite clear. Everything in the XDI graph has an XRI address. Since a predicate can not have more than one literal, it is sufficient to have the subject and predicate in the XRI address, e.g. =markus/+email.

2) Storing the whole graph data (including literals) as a set of XRIs - Bill says this is possible. And this is what my question (and I think Nat's too) was about.

Markus

On Sun, May 18, 2008 at 10:50 PM, Drummond Reed <drummond.reed@cordance.net> wrote:

Markus,

 

This subject has indeed come up several times before. I know Bill has suggested that, when looked at from an RDF graph standpoint, every XDI document can be represented as the set of RDF statements that appear in the document. This would include all those whose object is a literal.

 

However when we refer to "the set of XRIs" represented by an XDI RDF document, I have proposed that if the object of an XDI RDF statement is a literal, the literal is NOT part of the XRI. In other words, if you have the XDI RDF statement…

 

=markus
   +email
      "markus.sabadello@gmail.com"

 

…the XRI that identifies the literal object of this statement (using direct concatenation syntax) is:

 

            =markus/+email

 

That's as far as we've gone discussing it.

 

Is there any reason that rule will not work?

 

=Drummond

 

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From: Markus Sabadello [mailto:markus.sabadello@gmail.com]
Sent: Friday, May 16, 2008 6:12 PM

To: Bill Barnhill
Cc: Nat Sakimura; tatsuki@nri.com; xdi@lists.oasis-open.org
Subject: [xdi] XDI graph as XRIs

 

Hey Bill,

I'm sitting together with Nat and Tatsuki, talking about various XDI topics. One issue that came up was the following: I think it was you who suggested a few times that every XDI document can be expressed as a simple list of XRIs, right?

For example, if I have this XDI graph:

=markus
   +friend
      =bill.barnhill
      =drummond

I could just express it using these XRIs:

=markus/+friend/=bill.barnhill
=markus/+friend/=drummond

Right?

Now the question is, how does that work with literals? If I have this:

=markus
   +email
      "markus.sabadello@gmail.com"

Then what's the XRI that represents this statement? I'm sure someone has thought about that before, but I don't really remember how it works or if it works at all?

Markus