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Subject: Issue - 230 - Outgoing link from a fault handler
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In the last paragraph of "12.6 Flow",
In addition, a link that crosses a fault-handler boundary MUST be outbound, that is, it MUST have its source activity within the fault handler and its target activity within a scope that encloses the scope associated with the fault handler.What is the rationale behind the line above?
Example:
Scope A Sequence Scope B Sequence Scope C FaultHandler D Activity E Activity F Scope G Activity H Activity I
As far as I understand the specification,
Link from E:
I don't quite understand why we should allow/disallow linking as above.
Some may claim:
E to H is allowed, because it is within A, because it is WITHIN A,
although indirectly.
One of the problems is, IMHO, the definition of "WITHIN A SCOPE" is unclear.
Submitter's proposal: from Dieter Koenig1, 21 Oct 2005
Change the text in
In addition, a link that crosses a fault-handler boundary MUST be outbound, that is, it MUST have its source activity within the fault handler and its target activity within a scope that encloses the scope associated with the fault handler.
Replacing "within a scope that encloses" with "outside of", to make it:
In addition, a link that crosses a fault-handler boundary MUST be outbound, that is, it MUST have its source activity within the fault handler and its target activity outside of the scope associated with the fault handler.
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