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Subject: Other Haskell Errors
Line 4651 is wrong and should read: (i.e. the False should be True). all_of_any f [] ys = True The whole definition should be aligned as well so it is: all_of_any :: (a -> b -> Bool) -> [a ] -> [b] -> Bool all_of_any f [] ys = True all_of_any f (x:xs) ys = (any_of f x ys) && (all_of_any f xs ys) Cheers, -Polar
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