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Subject: xmlns:fo breaks xsl cust layer
Hi, Found this hack and decided it was a good idea for my current purpose. http://sources.redhat.com/ml/docbook-apps/2003-q2/msg00849.html But when I add the xmlns:fo to the xsl:stylesheet I get: F javax.xml.transform.TransformerException: ElemTemplateElement error: inline.boldmonoseq The offending parts are as follows: <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format" version="1.0"> <!-- Inline Formatting --> <xsl:template match="filename"> <xsl:call-template name="inline.boldmonoseq"/> </xsl:template> <xsl:template match="application"> <xsl:call-template name="inline.boldseq"/> </xsl:template> <xsl:template match="guibutton"> <xsl:call-template name="inline.boldseq"/> </xsl:template> <xsl:template match="guilabel"> <xsl:call-template name="inline.italicseq"/> </xsl:template> <!-- Page Break use <?pagebreak?;> to insert a page break --> <xsl:template match="processing-instruction('pagebreak')"> <fo:block break-after="page"/> </xsl:template> When I comment the whole of the Inline Formatting templates the xsl is valid. Any ideas? --------------------------------------------------------------------------------------------------- Sean Wheller
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